How to run a function when the page is loaded?(页面加载时如何运行函数?)
问题描述
I want to run a function when the page is loaded, but I don’t want to use it in the <body>
tag.
I have a script that runs if I initialise it in the <body>
, like this:
function codeAddress() {
// code
}
<body onLoad="codeAddress()">
But I want to run it without the <body onload="codeAddress()">
and I have tried a lot of things, e.g. this:
window.onload = codeAddress;
But it is not working.
So how do I run it when the page is loaded?
window.onload = codeAddress;
should work - here's a demo, and the full code:
<!DOCTYPE html>
<html>
<head>
<title>Test</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script type="text/javascript">
function codeAddress() {
alert('ok');
}
window.onload = codeAddress;
</script>
</head>
<body>
</body>
</html>
<!DOCTYPE html>
<html>
<head>
<title>Test</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script type="text/javascript">
function codeAddress() {
alert('ok');
}
</script>
</head>
<body onload="codeAddress();">
</body>
</html>
这篇关于页面加载时如何运行函数?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:页面加载时如何运行函数?


基础教程推荐
- npm start 错误与 create-react-app 2022-01-01
- 即使用户允许,Gmail 也会隐藏外部电子邮件图片 2022-01-01
- Bokeh Div文本对齐 2022-01-01
- Fabric JS绘制具有活动形状的多边形 2022-01-01
- 在 contenteditable 中精确拖放 2022-01-01
- 如何添加到目前为止的天数? 2022-01-01
- fetch 是否支持原生多文件上传? 2022-01-01
- 检查 HTML5 拖放文件类型 2022-01-01
- 原生拖动事件后如何获取 mouseup 事件? 2022-01-01
- Bootstrap 模态出现在背景下 2022-01-01