如何使用 jQuery 选择所有复选框?

How to select all checkboxes with jQuery?(如何使用 jQuery 选择所有复选框?)

问题描述

我需要有关 jQuery 选择器的帮助.假设我有一个如下所示的标记:

I need help with jQuery selectors. Say I have a markup as shown below:

<form>
  <table>
    <tr>
      <td><input type="checkbox" id="select_all" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
  </table>
</form>

当用户点击时如何获取除#select_all之外的所有复选框?

How to get all checkboxes except #select_all when user clicks on it?

推荐答案

一个更完整的例子，应该适用于你的情况:

A more complete example that should work in your case:

$('#select_all').change(function() {
  var checkboxes = $(this).closest('form').find(':checkbox');
  checkboxes.prop('checked', $(this).is(':checked'));
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form>
  <table>
    <tr>
      <td><input type="checkbox" id="select_all" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
  </table>
</form>

当#select_all复选框被点击时，复选框的状态被选中，当前表单中的所有复选框都设置为相同状态.

When the #select_all checkbox is clicked, the status of the checkbox is checked and all the checkboxes in the current form are set to the same status.

请注意，您不需要从选择中排除 #select_all 复选框，因为它的状态与所有其他复选框相同.如果你出于某种原因确实需要排除 #select_all，你可以使用这个:

Note that you don't need to exclude the #select_all checkbox from the selection as that will have the same status as all the others. If you for some reason do need to exclude the #select_all, you can use this:

$('#select_all').change(function() {
  var checkboxes = $(this).closest('form').find(':checkbox').not($(this));
  checkboxes.prop('checked', $(this).is(':checked'));
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form>
  <table>
    <tr>
      <td><input type="checkbox" id="select_all" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
    <tr>
      <td><input type="checkbox" name="select[]" /></td>
    </tr>
  </table>
</form>

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