ldapsearch 到 ldapjs 的转换

Ldapsearch to ldapjs conversion(ldapsearch 到 ldapjs 的转换)

问题描述

我一直在尝试转换以下 ldapsearch 查询

I've been trying to convert the following ldapsearch query

ldapsearch -H ldap://ldap.berkeley.edu -x -b 'ou=people,dc=berkeley,dc=edu' objectclass=*

到 ldapjs 脚本:

var ldap = require('ldapjs');
var server = 'ldap://ldap.berkeley.edu';
var searchBase = 'ou=people,dc=berkeley,dc=edu';

var client = ldap.createClient({
  url: server
});

var opts = {
  filter: '(objectclass=*)'
}; 

client.search(searchBase, opts, function(err, res) {
  res.on('searchEntry', function (entry) {
    console.log(entry.toString());
  });
});

ldapsearch 给了我很多结果，但 ldapjs 没有返回任何用户.
您可以在 GitHub 上找到解决此问题的一些尝试.

The ldapsearch gives me plenty of results but ldapjs doesn't return any users.
You can find some attempts of solving this on GitHub.

推荐答案

ldapjs 搜索范围是从 UMich 代码派生的 OpenLDAP 和 (AFAIK) 最相似的 C 库的倒退".ldapjs 中的默认范围是base"，而不是sub".在没有看到任何数据的情况下，您可能需要使该代码看起来像:

ldapjs search scopes are "backwards" of OpenLDAP and (AFAIK) most similar C libraries that are derived from the UMich code. The default scope in ldapjs is "base", as opposed to "sub". Without seeing any of your data, you probably need to make that code look like:

var opts = {
  filter: '(objectclass=*)',
  scope: 'sub'
}; 

client.search(searchBase, opts, function(err, res) {
  res.on('searchEntry', function (entry) {
    console.log(entry.toString());
  });
});

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