Sequelize - 在 PostgreSQL 数组查询中不包含字符串

Sequelize - does not contain a string within a PostgreSQL array query(Sequelize - 在 PostgreSQL 数组查询中不包含字符串)

问题描述

我有一个名为 Staff 的 Sequelize 模型.上面有一个数组字段，描述如下:

I have a Sequelize model called Staff. On it there's an array field described as follows:

const Staff = sequelize.define("staff", {
    name: {
        type: DataTypes.STRING,
    },
    email: {
        type: DataTypes.STRING,
        unique: true
    },
    password: {
        type: DataTypes.STRING,
    },
    roles: {
        type: DataTypes.ARRAY(DataTypes.STRING)
    },
});

我正在尝试创建一个 GraphQL 端点，它为所有在其 roles 字段中没有instructor"的员工提供服务.

I'm trying to create a GraphQL end point which serves up all staff which don't have 'instructor' in their roles field.

我已阅读 this page of the docs，建议我使用Sequelize.Op的组合.所以我创建了这个:

I've read this page of the docs, suggesting that I use a combination of Sequelize.Op. So I created this:

return Staff.findAll({
        where: {
            roles: {
                [Sequelize.Op.not]: {[Sequelize.Op.contains]: ['instructor']},
            }
        }
    }
)

上面抛出错误:

"message": "values.map is not a function"

但是，如果我要尝试不是组合的查询，例如:

However, if I am to try a query which isn't a combo such as:

return models.Staff.findAll({
        where: {
            roles: {
                [Sequelize.Op.contains]: ['instructor']
            }
        }
    }
)

查询运行正常，这让我相信我可能有语法错误或对 Op 逻辑如何组合的误解.

The query runs properly, this leads me to believe I perhaps have a syntax error or misunderstanding of how Op logic is combined.

推荐答案

试试这个:

return models.Staff.findAll({
  where: {
    $not: {
      roles: {
        $contains: ['instructor'],
      },
    },
  },
})

子句 $not 必须在您的目标列之前.

The clause $not need to be prior than the column you target.

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