获取您自己的元组元素的数量......不仅仅是范围或序列

get the count of elements of tuples of your own...not just the range or sequence(获取您自己的元组元素的数量......不仅仅是范围或序列)

问题描述

下面的代码正在运行这个列表元组的前三个元素

The below code is running for first three elements of the tuple of this list

SS1=[(1, 2, 3, 4, 5), (1, 2, 3, 4, 6), (1, 2, 3, 5, 6), (1, 2, 4, 5, 6), (1, 3, 4, 5, 6), (2, 3, 4, 5, 6)]

from collections import Counter
c = Counter(elem[0:3] for elem in SS1)

for k, v in c.items():
    if (v > 0):
        print(k,v)

输出是:

(1, 2, 3) 3
(1, 2, 4) 1
(1, 3, 4) 1
(2, 3, 4) 1

但我的期望不仅仅是前三个元组......我想要元组 (0,2,3) 或元组 (1,2,4) 的计数器代码> 同样，我可以传递元组的任何三个位置并获取它的计数......我该怎么做?

But my expectation is not just for first three tuple...i want the counter for tuple (0,2,3) or tuple (1,2,4) likewise i can pass any three position of the tuple and get the count of it... How can I do this?

推荐答案

如果我从你的问题中理解是正确的，下面的代码将解决你的问题:

If what i understood from your question is correct, the code below will solve your issue:

SS1=[(1, 2, 3, 4, 5), (1, 2, 3, 4, 6), (1, 2, 3, 5, 6), (1, 2, 4, 5, 6), (1, 3, 4, 5, 6), (2, 3, 4, 5, 6)]

from collections import Counter

def get_new_list(a, pos):
    # Check if any element in pos is > than the length of the tuples
    if any(k >= len(min(SS1, key=lambda x: len(x))) for k in pos):
        return

    for k in a:
        yield tuple(k[j] for j in pos)

def elm_counter(elm):
    if not len(elm):
        return 

    c = Counter(elm)
    for k, v in c.items():
        if v > 0:
            print(k, v)

elm = list(get_new_list(SS1, (0, 2, 4)))
elm_counter(elm)
print('---')
elm = list(get_new_list(SS1, (1, 2, 4)))
elm_counter(elm)

输出:

(1, 3, 5) 1
(1, 3, 6) 2
(1, 4, 6) 2
(2, 4, 6) 1
---
(2, 3, 6) 2
(2, 3, 5) 1
(3, 4, 6) 2
(2, 4, 6) 1

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