在 Python 中，如何将警告视为异常?

In Python, how does one catch warnings as if they were exceptions?(在 Python 中，如何将警告视为异常?)

问题描述

我在 python 代码中使用的第三方库(用 C 编写)发出警告.我希望能够使用 try except 语法来正确处理这些警告.有没有办法做到这一点?

A third-party library (written in C) that I use in my python code is issuing warnings. I want to be able to use the try except syntax to properly handle these warnings. Is there a way to do this?

推荐答案

要将警告作为错误处理，只需使用以下代码:

To handle warnings as errors simply use this:

import warnings
warnings.filterwarnings("error")

在此之后，您将能够捕获与错误相同的警告，例如这将起作用:

After this you will be able to catch warnings same as errors, e.g. this will work:

try:
    some_heavy_calculations()
except RuntimeWarning:
    import ipdb; ipdb.set_trace()

附:添加此答案是因为评论中的最佳答案包含拼写错误:filterwarnigns 而不是 filterwarnings.

P.S. Added this answer because the best answer in comments contains misspelling: filterwarnigns instead of filterwarnings.

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