基于 IP 地址的地理位置 - PHP-php问题

Geo Location based on IP Address - PHP(基于 IP 地址的地理位置 - PHP)

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问题描述

我们正在寻找一种快速准确的方法来根据访问者的 IP 获取他们的位置.

We're looking for a fast and accurate way to get the visitors location based on their IP.

我们已经尝试过 ipinfodb.com，但他们的 API 在进行 API 调用时使我们的网站严重滞后.

We have tried ipinfodb.com but their API made our website severely lag when making the API call.

您还建议什么其他服务?

What other services do you suggest?

推荐答案

获取 Geo-IP 信息

Get Geo-IP Information

请求地理 IP 服务器 (netip.de) 进行检查，返回 IP 所在的位置(主机、州、国家、城镇).

Requests a geo-IP-server (netip.de) to check, returns where an IP is located (host, state, country, town).

<?php
       $ip='94.219.40.96';
       print_r(geoCheckIP($ip));
       //Array ( [domain] => dslb-094-219-040-096.pools.arcor-ip.net [country] => DE - Germany [state] => Hessen [town] => Erzhausen )

       //Get an array with geoip-infodata
       function geoCheckIP($ip)
       {
               //check, if the provided ip is valid
               if(!filter_var($ip, FILTER_VALIDATE_IP))
               {
                       throw new InvalidArgumentException("IP is not valid");
               }

               //contact ip-server
               $response=@file_get_contents('http://www.netip.de/search?query='.$ip);
               if (empty($response))
               {
                       throw new InvalidArgumentException("Error contacting Geo-IP-Server");
               }

               //Array containing all regex-patterns necessary to extract ip-geoinfo from page
               $patterns=array();
               $patterns["domain"] = '#Domain: (.*?)&nbsp;#i';
               $patterns["country"] = '#Country: (.*?)&nbsp;#i';
               $patterns["state"] = '#State/Region: (.*?)<br#i';
               $patterns["town"] = '#City: (.*?)<br#i';

               //Array where results will be stored
               $ipInfo=array();

               //check response from ipserver for above patterns
               foreach ($patterns as $key => $pattern)
               {
                       //store the result in array
                       $ipInfo[$key] = preg_match($pattern,$response,$value) && !empty($value[1]) ? $value[1] : 'not found';
               }

               return $ipInfo;
       }

?>

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