Laravel Eloquent 跳过 n，通吃?

织梦狗教程 php问题

2021-01-01

Laravel Eloquent skip n, take all?(Laravel Eloquent 跳过 n，通吃?)

本文介绍了Laravel Eloquent 跳过 n，通吃?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我注意到在 Laravel 中链接 skip() 时，您还必须使用 take() .我想跳过前 n 行但剩下的.take 方法只允许整数，我怎么能做到这一点而不诉诸一些技巧，例如为 take 指定一个大数字?

I've noticed that in Laravel when chaining a skip() you must also use take() as well. I want to skip the first n rows but take the rest. The take method only allows integers how can I do this without resorting to some hacky trick such as specifying a large number for take?

推荐答案

基本上，对于每个 OFFSET，必须为 mysql 提供一个 LIMIT 才能工作.因此，如果不指定限制，就无法做到这一点.我们需要一些 php mojo 才能在这里工作.

Basically, with every OFFSET, a LIMIT must be supplied for mysql to work. Therefore, there is no way to do this without sepcifying a limit. We need some php mojo to work here.

假设我们有一个名为 Attendance 的 Eloquent 类.以下是应该可行的:

Let's say we have an Eloquent Class named Attendance. Here's what should work:

//Getting count
$count = Attendance::count();
$skip = 5;
$limit = $count - $skip; // the limit
$collection = Attendance::skip($skip)->take($limit)->get();

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