如何将 PHP 数组编码为 JSON 数组，而不是对象?

How do I encode a PHP array to a JSON array, not object?(如何将 PHP 数组编码为 JSON 数组，而不是对象?)

问题描述

我正在尝试对从 Zend_DB 查询返回的数组进行 json_encode.

I am trying to json_encode an array which is returned from a Zend_DB query.

var_dump 给出:(手动添加 0 个成员不会改变图片.)

var_dump gives: (Manually adding 0 member does not change the picture.)

array(3) {
  [1]=>
  array(3) {
    ["comment_id"]=>
    string(1) "1"
    ["erasable"]=>
    string(1) "1"
    ["comment"]=>
    string(6) "test 1"
  }
  [2]=>
  array(3) {
    ["comment_id"]=>
    string(1) "2"
    ["erasable"]=>
    string(1) "1"
    ["comment"]=>
    string(6) "test 1"
  }
  [3]=>
  array(3) {
    ["comment_id"]=>
    string(1) "3"
    ["erasable"]=>
    string(1) "1"
    ["comment"]=>
    string(6) "jhghjg"
  }
}

编码后的字符串如下所示:

The encoded string looks like:

{"1":{"comment_id":"1","erasable":"1","comment":"test 1"},
 "2":{"comment_id":"2","erasable":"1","comment":"test 1"},
 "3":{"comment_id":"3","erasable":"1","comment":"jhghjg"}}

我需要的是:

[{"comment_id":"1","erasable":"1","comment":"test 1"},
{"comment_id":"2","erasable":"1","comment":"test 1"},
{"comment_id":"3","erasable":"1","comment":"jhghjg"}]

php.ini/json_encode 文档说它应该是什么样子.

Which is what the php.ini/json_encode documentation says it should look like.

推荐答案

您如何设置初始数组?

如果你这样设置:

array(
 "1" => array(...),
 "2" => array(...),
);

那么你没有一个带有数字索引的数组，而是字符串，在 JS 世界中它被转换为一个对象.如果您没有设置严格的顺序(即从 0 而不是 1 开始)，也会发生这种情况.

then you don't have an array with numeric indexes but strings, and that's converted to an object in JS world. This can happen also if you don't set a strict order (i.e. starting at 0 instead of 1).

然而，这是在黑暗中拍摄，因为我看不到您的原始代码:首先尝试在不使用键的情况下设置您的数组:

This is a shot in the dark, however, because I can't see your original code: try setting your array without using keys at all in the first place:

array(
 array(...),
 array(...),
);

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