我如何获得特定类的 td nodeValue?-php问题

How i can get td nodeValue with specific class?(我如何获得特定类的 td nodeValue?)

本文介绍了我如何获得特定类的 td nodeValue?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有以下 html 表:

I have following html table:

<table>
    <tr>
        <td><img src="name0.gif" alt="Name0" /></td>
        <td <img src="name1.gif" alt="Name1" /></td>
        <td <img src="name2.gif" alt="Name2" /></td>
        <td <img src="name3.gif" alt="Name3" /></td>
        <td <img src="name4.gif" alt="Name4" /></td>
    </tr>
    <tr>
        <td class="name_con" >Name0</td>
        <td class="name_con" >Name1</td>
        <td class="name_con" >Name2</td>
        <td class="name_con" >Name3</td>
        <td class="name_con" >Name4</td>
    </tr>
</table>


如何使用 class="name_con" 获取 nodeValues??
how I can get nodeValues with class="name_con"??
我只知道从基本形式获取所有 td:
I only know get all td from basic form:
$dom = new DOMDocument();
$dom->loadHTMLFile($web);
$tables = $dom->getElementsByTagName('td');
//I want create a new table from max to min.
echo "<table>";
//this for is only for testing
for ($i = 9; $i > 0; $i--){
    $table = $tables->item($i);
    echo "<tr><td>".$table->nodeValue."</td></tr>";
}
echo "</table>";


推荐答案

使用 <代码>getAttribute():

for ($i = 9; $i > 0; $i--){
    $table = $tables->item($i);
    if ($table->getAttribute('class') == 'name_con') {
        echo "<tr><td>".$table->nodeValue."</td></tr>
";
    }
}

这也可以使用 XPath 表达式:

This is also possible with an XPath expression:

$xpath = new DOMXPath($dom);
$nodes = $xpath->query('//td[contains(@class,"name_con")]');

echo "<table>";
foreach ($nodes as $node) {
    echo "<tr><td>".$node->nodeValue."</td></tr>
";
}
echo "</table>";

这篇关于我如何获得特定类的 td nodeValue?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！