Popup menu on click of a button in action Bar(单击操作栏中的按钮时弹出菜单)
本文介绍了单击操作栏中的按钮时弹出菜单的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
I am trying to implement an action bar in which one of the buttons on click shows a popup menu. Here's the menu. XML (menu items in the action bar)
<menu xmlns:android="http://schemas.android.com/apk/res/android" >
<item
android:id="@+id/search"
android:icon="@drawable/ic_action_search"
android:orderInCategory="0"
android:showAsAction="always"
android:title="@string/menu_search"/>
<item
android:id="@+id/refresh"
android:icon="@drawable/ic_action_refresh"
android:orderInCategory="1"
android:showAsAction="always"
android:title="@string/menu_refresh"/>
<Item
android:id="@+id/popup"
android:icon="@drawable/ic_action_search"
android:onClick="showPopup"
android:orderInCategory="1"
android:showAsAction="always"
android:title="@string/menu_search" />
I wish to show a popup menu on the click of the item having id "@+id/popup".
here is the XML for the popup menu
<menu xmlns:android="http://schemas.android.com/apk/res/android" >
<item
android:id="@+id/item1"
android:icon="@drawable/ic_action_search"
android:orderInCategory="0"
android:showAsAction="always"
android:title="@string/menu_search"/>
<item
android:id="@+id/item2"
android:icon="@drawable/ic_action_search"
android:orderInCategory="1"
android:showAsAction="always"
android:title="@string/menu_search"/>
here is the onClick method for the button
public void showPopup(View v) {
PopupMenu popup = new PopupMenu(this, v);
MenuInflater inflater = popup.getMenuInflater();
inflater.inflate(R.menu.overflow, popup.getMenu());
popup.show();
}
And the problem is that no popup shows up on click of that button. Need help folks.
解决方案
I found a solution to this. Instead to using the menu XML to inflate the popup menu, I made a XML layout file.
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/container"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="#8b8989"
android:orientation="vertical"
android:padding="10dip" >
<TextView
android:id="@+id/menuItem1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginTop="10dip"
android:text="@string/menu1" />
<TextView
android:id="@+id/menuItem2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginTop="10dip"
android:text="@string/menu2" />
<TextView
android:id="@+id/menuItem3"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_marginTop="10dip"
android:text="@string/menu3" />
</LinearLayout>
and i changed the onClick method
public void showPopup(View v) {
LayoutInflater inflater = (LayoutInflater) MainActivity.this
.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
PopupWindow pw = new PopupWindow(inflater.inflate(
R.layout.overflow_layout, null, false), 300, 400, true);
pw.showAtLocation(findViewById(R.id.container), Gravity.CENTER, 0,
0);
}
This solved the issue
这篇关于单击操作栏中的按钮时弹出菜单的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
织梦狗教程
本文标题为:单击操作栏中的按钮时弹出菜单


基础教程推荐
猜你喜欢
- libGDX 从精灵或纹理中获取像素颜色 2022-01-01
- iOS4 创建后台定时器 2022-01-01
- iPhone - 获取给定地点/时区的当前日期和时间并将其与同一地点的另一个日期/时间进行比较的正确方法 2022-01-01
- Cocos2d iPhone 非矩形精灵触摸检测 2022-01-01
- navigator.geolocation.getCurrentPosition 在 Android 浏览器上 2022-01-01
- Android:getLastKnownLocation(LocationManager.NETWORK_PROVIDER 2022-01-01
- AdMob 广告未在模拟器中显示 2022-01-01
- 如何从 logcat 中删除旧数据? 2022-01-01
- NSString intValue 不能用于检索电话号码 2022-01-01
- 通过重定向链接在 Google Play 中打开应用 2022-01-01