Android 位置管理器，获取 GPS 位置，如果没有 GPS 则获取网络提供商位置

Android Location Manager, Get GPS location ,if no GPS then get to Network Provider location(Android 位置管理器，获取 GPS 位置，如果没有 GPS 则获取网络提供商位置)

问题描述

我正在使用下面给出的代码来获取位置:

I am using this given below code to get locations:

public Location getLocation() {
        try {
            mLocationManager = (LocationManager) context.getSystemService(LOCATION_SERVICE);

            // getting GPS status
            boolean isGPSEnabled = mLocationManager.isProviderEnabled(LocationManager.GPS_PROVIDER);

            // getting network status
            boolean isNetworkEnabled = mLocationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER);

            if (!isGPSEnabled && !isNetworkEnabled) {
                // no network provider is enabled
            } else {
                // First get location from Network Provider
                if (isNetworkEnabled) {
                    mLocationManager.requestLocationUpdates( LocationManager.NETWORK_PROVIDER,  MIN_TIME_BW_UPDATES,  MIN_DISTANCE_CHANGE_FOR_UPDATES, this);
                    Log.d("Network", "Network");
                    if (mLocationManager != null) {
                        location = mLocationManager.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);
                        if (location != null) {
                            lat = location.getLatitude();
                            lng = location.getLongitude();
                        }
                    }
                }
                //get the location by gps
                if (isGPSEnabled) {
                    if (location == null) {
                        mLocationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER,MIN_TIME_BW_UPDATES,MIN_DISTANCE_CHANGE_FOR_UPDATES, this);
                        Log.d("GPS Enabled", "GPS Enabled");
                        if (mLocationManager != null) {location = mLocationManager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
                            if (location != null) {
                                lat = location.getLatitude();
                                lng = location.getLongitude();
                            }
                        }
                    }
                }
            }

        } catch (Exception e) {
            e.printStackTrace();
        }

        return location;
    }

它工作正常，但我想先获取 GPS 位置，如果它不可用，位置管理器应该查询网络提供商，我遇到了麻烦.

It is working properly, but I would like to get GPS location first, and in case if it is unavailable , location manager should query for Network provider, in which I am getting trouble.

请推荐我这样做的好方法.

Please, recommend me the good way to do this.

推荐答案

你说你首先需要 GPS 位置(如果可用)，但你所做的是首先从网络提供商那里获取位置，然后从 GPS 获取.如果两者都可用，这也将从网络和 GPS 获取位置.您可以做的是，将这些案例写在 if..else if 块中.类似于-

You're saying that you need GPS location first if its available, but what you did is first you're getting location from network provider and then from GPS. This will get location from Network and GPS as well if both are available. What you can do is, write these cases in if..else if block. Similar to-

if( !isGPSEnabled && !isNetworkEnabled) {

// Can't get location by any way

} else {

    if(isGPSEnabled) {

    // get location from GPS

    } else if(isNetworkEnabled) {

    // get location from Network Provider

    }
}

所以这将首先从 GPS 获取位置(如果可用)，否则它将尝试从网络提供商获取位置.

So this will fetch location from GPS first (if available), else it will try to fetch location from Network Provider.

编辑:

为了使它更好，我将发布一个片段.考虑它在 try-catch 中:

To make it better, I'll post a snippet. Consider it is in try-catch:

boolean gps_enabled = false;
boolean network_enabled = false;

LocationManager lm = (LocationManager) mCtx
                .getSystemService(Context.LOCATION_SERVICE);

gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
network_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);

Location net_loc = null, gps_loc = null, finalLoc = null;

if (gps_enabled)
    gps_loc = lm.getLastKnownLocation(LocationManager.GPS_PROVIDER);
if (network_enabled)
    net_loc = lm.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);

if (gps_loc != null && net_loc != null) {

    //smaller the number more accurate result will
    if (gps_loc.getAccuracy() > net_loc.getAccuracy()) 
        finalLoc = net_loc;
    else
        finalLoc = gps_loc;

        // I used this just to get an idea (if both avail, its upto you which you want to take as I've taken location with more accuracy)

} else {

    if (gps_loc != null) {
        finalLoc = gps_loc;
    } else if (net_loc != null) {
        finalLoc = net_loc;
    }
}

现在你检查 finalLoc 是否有 null，如果没有则 return 它.您可以在返回所需 (finalLoc) 位置的函数中编写上述代码.我认为这可能会有所帮助.

Now you check finalLoc for null, if not then return it. You can write above code in a function which returns the desired (finalLoc) location. I think this might help.

这篇关于Android 位置管理器，获取 GPS 位置，如果没有 GPS 则获取网络提供商位置的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！