concatenation of string constants in java(java中字符串常量的连接)
问题描述
In C++, the best canonical way to create a multiline string of which I am aware is to create adjacent strings and let the compiler concatenate them at compile time, like this:
string s = "This is a very long string ...
"
" and it keeps on going...";
In Java, the only way I know to do this is with concatenation:
String s = "This is a very long string ...
" +
" and it keeps on going...";
The question is, does this generate a single string at runtime, or does java actually concatenate at compile time also? The reason the question comes up is because of the following behavior:
String s1 = "abc";
String s2 = "abc";
System.out.println(s1 == s2); // this prints true, because the compiler
// generates only one "abc" object
String s3 = "a";
s3 += "bc";
System.out.println(s1 == s3); // false
String s3 = "a";
s3 += "bc";
Is same as:
String s3 = "a";
s3 = new StringBuilder().append(s3).append("bc").toString();
So it creates a new instance of String.
You can even try:
String s = null;
s += null;
System.out.println(s); // prints "nullnull"
这篇关于java中字符串常量的连接的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:java中字符串常量的连接
基础教程推荐
- Struts2 URL 无法访问 2022-01-01
- 存储 20 位数字的数据类型 2022-01-01
- 修改 void 函数的输入参数,然后读取 2022-01-01
- REST Web 服务返回 415 - 不支持的媒体类型 2022-01-01
- 如何对 Java Hashmap 中的值求和 2022-01-01
- RabbitMQ:消息保持“未确认"; 2022-01-01
- 问题http://apache.org/xml/features/xinclude测试日志4j 2 2022-01-01
- 使用堆栈算法进行括号/括号匹配 2022-01-01
- 无法复制:“比较方法违反了它的一般约定!" 2022-01-01
- Spring AOP错误无法懒惰地为此建议构建thisJoinPoin 2022-09-13
