如何使用任何空白字符作为分隔符拆分字符串

How to split a string with any whitespace chars as delimiters(如何使用任何空白字符作为分隔符拆分字符串)

问题描述

我需要将什么正则表达式模式传递给 java.lang.String.split() 以使用所有空白字符 (' ' 将字符串拆分为子字符串数组>、' '、' ' 等)作为分隔符?

What regex pattern would need I to pass to java.lang.String.split() to split a String into an Array of substrings using all whitespace characters (' ', ' ', ' ', etc.) as delimiters?

推荐答案

有些东西

myString.split("\s+");

这会将所有空格分组为分隔符.

This groups all white spaces as a delimiter.

所以如果我有字符串:

"Hello[space character][tab character]World"

这应该产生字符串 Hello" 和 World" 并省略 [space] 和[tab].

This should yield the strings "Hello" and "World" and omit the empty space between the [space] and the [tab].

正如 VonC 指出的那样，应该转义反斜杠，因为 Java 会首先尝试将字符串转义为特殊字符，然后发送 that 进行解析.你想要的是文字s"，这意味着，你需要传递\s".可能会有点混乱.

As VonC pointed out, the backslash should be escaped, because Java would first try to escape the string to a special character, and send that to be parsed. What you want, is the literal "s", which means, you need to pass "\s". It can get a bit confusing.

\s 等价于 [ \t\n\x0B\f\r].

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