mockito anyList 给定大小

mockito anyList of a given size(mockito anyList 给定大小)

问题描述

我正在使用 mockito 验证一个方法已被调用.方法:

I'm verifying with mockito that a method has been called. The method:

public void createButtons(final List<Button> buttonsConfiguration) {...}

由于传递哪个列表并不重要，因此我验证该方法的调用如下:

Since It doesn't matter which list is passed I verify that the method is called as follows:

verify(mock).createButtons(Matchers.anyListOf(Button.class));

但是，List 的大小很重要.因此，哪个 List 并不重要，但列表必须有 X 个元素.

But, the size of the List is important. So, it doesn't matter which List but the list has to have X elements.

这可能吗?

推荐答案

一种方法是使用 Captor

One way is to use a Captor

ArgumentCaptor<List> captor = ArgumentCaptor.forClass(List.class);
verify(mock).createButtons(captor.capture());
assertEquals(x, captor.getValue().size()); // if expecting single list
assertEquals(x, captor.getValues().size()); // if expecting multiple lists

请参阅 http://docs.mockito.googlecode.com/hg/org/mockito/Mockito.html#15 获取文档.

您还可以使用自定义参数匹配器.该文档显示了一个完全符合您要求的示例:

You could also use a custom argument matcher. The documentation shows an example that does exactly what you want:

http://docs.mockito.googlecode.com/hg/org/mockito/ArgumentMatcher.html

 class IsListOfTwoElements extends ArgumentMatcher<List> {
     public boolean matches(Object list) {
         return ((List) list).size() == 2;
     }
 }
 
 List mock = mock(List.class);
 when(mock.addAll(argThat(new IsListOfTwoElements()))).thenReturn(true);
 mock.addAll(Arrays.asList("one", "two"));
 verify(mock).addAll(argThat(new IsListOfTwoElements()));

例如，您还可以添加一个构造函数，以便指定所需的列表大小等.

You could, for instance, also add a constructor so you can specify list size desired, etc.

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