Java整数解析错误

Java Integer parseInt error(Java整数解析错误)

问题描述

我有以下问题:

我想将一些二进制字符串转换为整数:

I want to convert some Binary Strings to an integer:

eargb = Integer.parseInt(al + re + gre + blu, 2);

但我得到以下异常.为什么?

but I get following exception. Why?

java.lang.NumberFormatException: For input string: "11111111111000101000100111111010"

推荐答案

您的数字 (4,293,036,538) 太大而无法放入带符号的 int(范围为 -2,147,483,648 到 2,147,483,647)中.

Your number (4,293,036,538) is too large to fit in a signed int (which has a range of -2,147,483,648 to 2,147,483,647).

尝试使用 long 来代替.这个范围更大.

Try using a long instead. This has a larger range.

这篇关于Java整数解析错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！