FileLocator.resolve(url) 的转义结果-Java问题

Escape result of FileLocator.resolve(url)(FileLocator.resolve(url) 的转义结果)

本文介绍了FileLocator.resolve(url) 的转义结果的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

FileLocator.resolve(url) 方法可用于将地址 bundleentry://something/somewhere/x.txt 转换为适合 <代码>/mnt/foo/somewhere/x.txt.

The method FileLocator.resolve(url) can be used to translate an address bundleentry://something/somewhere/x.txt to a proper file URL for /mnt/foo/somewhere/x.txt.

但是，这也记录在 https://bugs.eclipse.org/bugs/show_bug.cgi?id=145096，URL 没有转义.例如，如果包含引用包的 Eclipse 安装位于包含空格的目录中，则 FileLocator.resolve 返回的 URL 仍然包含空格并调用 url.toURI()因此而失败.


However, which is also documented at https://bugs.eclipse.org/bugs/show_bug.cgi?id=145096, the URL is not escaped. As an example, if the Eclipse installation containing the referenced bundle is in a directory containing a space, the URL returned by FileLocator.resolve still contains the space and calling url.toURI() fails because of that.
如何手动转义 URL 中的所有个必要字符?
如何根据相对于当前路径的路径获取 File 对象捆绑?


How can I manually escape all necessary characters in the URL?
How can I get a File object based on a path relative to the current
bundle?

作为参考，如果该文件位于包含空格的目录中，则尝试在插件的 .jar 文件中查找目录 dir 时失败的代码如下:
As reference, here is the code that fails when trying to find the directory dir inside my plugin's .jar file if that file is in a directory containing a space:
    final IPath pathOfExampleProject = new Path("dir");
    final Bundle bundle = Platform.getBundle(AproveIDs.PLUGIN_ID);
    final URL url = FileLocator.find(bundle, pathOfExampleProject, null);
    final URL url2 = FileLocator.toFileURL(url);
    url2.toURI(); // Illegal character in path at index [...]


推荐答案
我刚找到这段代码:
http://code.google.com/p/dart/source/browse/branches/bleeding_edge/dart/editor/tools/plugins/com.google.dart.tools.core/src/com/google/dart/tools/core/internal/model/BundledSystemLibrary.java?r=2057
相关行确实有帮助:
// We need to use the 3-arg constructor of URI in order to properly escape file system chars.
URI resolvedUri = new URI(resolvedUrl.getProtocol(), resolvedUrl.getPath(), null);


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