使用 JAXB 将 JSON 编组/解组到 Java 类-Java问题

Marshall/Unmarshall a JSON to a Java class using JAXB(使用 JAXB 将 JSON 编组/解组到 Java 类)

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问题描述

我正在使用 JAX-RS 和 JAXB 注释成功地将 POJO 编组为 JSON.

I am successfully marshaling a POJO into JSON using JAX-RS and JAXB annotations.

问题是，当我尝试使用它来取消编组我的请求时，它不起作用.据我在文档 JAX-RS 可以自动将应用程序/json 字符串编组和解组回 java 类.

The problem is that when I am trying to use the same for un-marshalling my request it doesn’t work. As far as I can see in the documentation JAX-RS can automatically marshal and unmarshal application/json strings back to java classes.

我是否需要为此创建自己的 MessageBodyReader，或者这是由框架支持而不使用 Jackson 库?

Do I need to create my own MessageBodyReader for that, or this is supported by the framework without using Jackson libraries?

推荐答案

编组为 XML 很容易，但我花了一段时间才弄清楚如何编组为 JSON.找到解决方案后就很简单了.

Marshalling to XML is easy, but it took me a while to figure out how to marshall to JSON. Pretty simple after you find the solution though.

public static String marshalToXml( Object o ) throws JAXBException {

    StringWriter writer = new StringWriter();
    Marshaller marshaller = JAXBContext.newInstance( o.getClass() ).createMarshaller();
    marshaller.setProperty( Marshaller.JAXB_FORMATTED_OUTPUT, true );
    marshaller.marshal( o, writer );
    return writer.toString();
}

public static String marshalToJson( Object o ) throws JAXBException {

    StringWriter writer = new StringWriter();
    JAXBContext context = JSONJAXBContext.newInstance( o.getClass() );

    Marshaller m = context.createMarshaller();
    JSONMarshaller marshaller = JSONJAXBContext.getJSONMarshaller( m );
    marshaller.setProperty( Marshaller.JAXB_FORMATTED_OUTPUT, true );
    marshaller.marshallToJSON( o, writer );
    return writer.toString();
}

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