读取输入，直到输入特定数字

Read input until a certain number is typed(读取输入，直到输入特定数字)

问题描述

当输入零并立即开始求和时，我需要停止询问整数输入.当我输入零时，我的程序不会停止.我需要它停止并开始总结它收集的所有输入.

I need to stop asking for integer inputs when zero is typed as an input and start summation immediately. My program doesn't stop when I type zero. I need it to stop and start summing up all the inputs it has gathered.

这是我所拥有的:

public class Inttosum {

    public static void main(String[] args) {
        System.out.println("Enter an integer");
        Scanner kb = new Scanner(System.in);
        int askool = kb.nextInt();
        int sum = 0;
        int score = 0;


        while(askool != 0){
          score = kb.nextInt();
          sum += score;
        }
    }
}

///////////////最终代码有效..谢谢！公共类 Inttosum {

/////////////////The final code which worked..Thank you! public class Inttosum {

    public static void main(String[] args) {
        System.out.println("Enter an integer");

    Scanner kb = new Scanner(System.in);
    int sum = 0;
    int score = 0;
    do {
        score = kb.nextInt();
        sum += score;

    }while(score != 0);
    System.out.print(sum); 
 }
}

推荐答案

do-while

您正在使用称为 askool 的东西作为循环条件，但在循环中更新变量 score.您可以使用 do-while 循环.改变

do-while

You are using something called askool as a loop condition, but updating the variable score in your loop. You could use a do-while loop. Change

while(askool != 0){
    score = kb.nextInt();
    sum += score;
}

类似

do {
    score = kb.nextInt();
    sum += score;
}while(score != 0);

使用 break

我还建议调用 Scanner.hasNextInt() 在调用 nextInt 之前.而且，由于你不使用 score(只是 sum)你可以这样写，

Using break

I also suggest calling Scanner.hasNextInt() before calling nextInt. And, since you don't use the score (just the sum) you could write it like,

int sum = 0;
while (kb.hasNextInt()) {
    int score = kb.nextInt();
    if (score == 0) {
        break;
    }
    sum += score;
}
System.out.print(sum);

如果用户输入文本，它也会停止(并且仍然 sum 所有 ints).

Which will also stop (and still sum all ints) if the user enters text.

这篇关于读取输入，直到输入特定数字的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！