如何按 SQL 中的任意条件排序

How to order by an arbitrary condition in SQL(如何按 SQL 中的任意条件排序)

问题描述

我有下表:

CREATE TABLE Bable(id int 身份主键，名称 varchar(20),关于 varchar(30));INSERT INTO Bable (name,about) VALUES('ООО Name Firm 1','texttexttexttext'),('ООО Name Firm 2','texttexttexttext'),('ООО Name Firm 3','texttexttexttext'),('ООО Name Firm 4','texttexttexttext'),('ООО Name Firm 5','texttexttexttext'),('ООО Name Firm $1','texttexttexttext'),('ООО Name Firm $2','texttexttexttext'),('ООО Name Firm $3','texttexttexttext'),('ООО Name Firm 6','texttexttexttext'),('ООО Name Firm 7','texttexttexttext')

我可以编写如下查询:

SELECT * FROM Bable WHERE about = 'texttexttexttext'

如何更改此查询以返回排序的结果，使得名称包含$"的那些首先出现，然后是那些不出现的，然后每个组按 name 升序排列?

表格结构在这里

SELECT *从 BableORDER BY CASE WHEN name LIKE '%$..' THEN 0 ELSE 1 END，姓名

• SQLFiddle 演示

I have the following table:

CREATE TABLE Bable
    (
     id int identity primary key, 
     name varchar(20), 
     about varchar(30)
    );
INSERT INTO Bable (name,about) VALUES
('ООО Name Firm 1','texttexttexttext'),
('ООО Name Firm 2','texttexttexttext'),
('ООО Name Firm 3','texttexttexttext'),
('ООО Name Firm 4','texttexttexttext'),
('ООО Name Firm 5','texttexttexttext'),
('ООО Name Firm $1','texttexttexttext'),
('ООО Name Firm $2','texttexttexttext'),
('ООО Name Firm $3','texttexttexttext'),
('ООО Name Firm 6','texttexttexttext'),
('ООО Name Firm 7','texttexttexttext')

And I can write a query like the following:

SELECT * FROM Bable WHERE about = 'texttexttexttext'

How can I alter this query to return results ordered such that those with names containing "$" appear first, followed by those that do not, with each group then ordered by name ascending?

Structure of the table is here

SELECT *
FROM   Bable
ORDER  BY CASE WHEN name LIKE '%$..' THEN 0 ELSE 1 END,
          Name 

• SQLFiddle Demo

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