如何使用 Laravel 的流畅查询构建器选择计数?

How to select count with Laravel#39;s fluent query builder?(如何使用 Laravel 的流畅查询构建器选择计数?)

问题描述

这是我使用 fluent 查询构建器的查询.

Here is my query using fluent query builder.

    $query = DB::table('category_issue')
        ->select('issues.*')
        ->where('category_id', '=', 1)
        ->join('issues', 'category_issue.issue_id', '=', 'issues.id')
        ->left_join('issue_subscriptions', 'issues.id', '=', 'issue_subscriptions.issue_id')
        ->group_by('issues.id')
        ->order_by(DB::raw('COUNT(issue_subscriptions.issue_id)'), 'desc')
        ->get();

如您所见，我按连接表中的计数进行排序.这工作正常.但是，我希望此计数与我的选择一起返回.

As you can see, I am ordering by a count from the joined table. This is working fine. However, I want this count returned with my selections.

这是我的原始续集查询，效果很好.

Here is the my raw sequel query that works fine.

Select issues.*, COUNT(issue_subscriptions.issue_id) AS followers 
FROM category_issue JOIN Issues ON category_issue.issue_id = issues.id 
LEFT JOIN issue_subscriptions ON issues.id = issue_subscriptions.issue_id
WHERE category_issue.category_id = 1
GROUP BY issues.id
ORDER BY followers DESC

我将如何使用 Laravel 的流畅查询构建器进行这个选择?我知道我可以使用原始 sql 查询，但我想尽可能避免这种情况.任何帮助将不胜感激，提前致谢！

How would I go about this select using Laravel's fluent query builder? I am aware I can use a raw sql query but I would like to avoid that if possible. Any help would be appreciated, thanks in advance!

推荐答案

你可以在 select() 中使用一个数组来定义更多的列，你可以在那里使用 DB::raw() 并将其别名给关注者.应该是这样的:

You can use an array in the select() to define more columns and you can use the DB::raw() there with aliasing it to followers. Should look like this:

$query = DB::table('category_issue')
    ->select(array('issues.*', DB::raw('COUNT(issue_subscriptions.issue_id) as followers')))
    ->where('category_id', '=', 1)
    ->join('issues', 'category_issue.issue_id', '=', 'issues.id')
    ->left_join('issue_subscriptions', 'issues.id', '=', 'issue_subscriptions.issue_id')
    ->group_by('issues.id')
    ->order_by('followers', 'desc')
    ->get();

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