如何从 Python 中的数据库创建 CSV 文件?

How do I create a CSV file from database in Python?(如何从 Python 中的数据库创建 CSV 文件?)

问题描述

我有一个名为clients"的 Sqlite 3 和/或 MySQL 表..

I have a Sqlite 3 and/or MySQL table named "clients"..

使用 python 2.6，我如何创建一个名为 Clients100914.csv 的带有标题的 csv 文件?excel方言...

Using python 2.6, How do I create a csv file named Clients100914.csv with headers? excel dialect...

Sql 执行:select * 只提供表数据，但我想要带有标题的完整表.

The Sql execute: select * only gives table data, but I would like complete table with headers.

如何创建记录集以获取表头.表头应该直接来自不是用 python 编写的 sql.

How do I create a record set to get table headers. The table headers should come directly from sql not written in python.

w = csv.writer(open(Fn,'wb'),dialect='excel')
#w.writelines("header_row")
#Fetch into sqld
w.writerows(sqld)

这段代码让我打开文件并且没有标题.也无法弄清楚如何使用文件作为日志.

This code leaves me with file open and no headers. Also cant get figure out how to use file as log.

推荐答案

import csv
import sqlite3

from glob import glob; from os.path import expanduser
conn = sqlite3.connect( # open "places.sqlite" from one of the Firefox profiles
    glob(expanduser('~/.mozilla/firefox/*/places.sqlite'))[0]
)
cursor = conn.cursor()
cursor.execute("select * from moz_places;")
with open("out.csv", "w", newline='') as csv_file:  # Python 3 version    
#with open("out.csv", "wb") as csv_file:              # Python 2 version
    csv_writer = csv.writer(csv_file)
    csv_writer.writerow([i[0] for i in cursor.description]) # write headers
    csv_writer.writerows(cursor)

PEP 249 (DB API 2.0) 有更多关于cursor.description.

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