C++ 中指针的分段错误

Segmentation Fault with Pointers in C++(C++ 中指针的分段错误)

问题描述

我正在尝试构建结构的对象，但在分配值时遇到分段错误.在我构建对象后，它将通过指针传递到列表中.这是我的实现:

I am trying to build an object of a struct but am getting a segmentation fault while assigning the values. After I build the object it will be passed by pointer into a list. Here is my implementation:

struct clientInfo {
  int client, a, b;
};
List *info=new List();

void thread(int which) {
  clientInfo *cI;
  cI->client=which;
  cI->a=4;
  cI->b=5;
  info->Append(cI);
}

在执行 'cI->client=which' 期间，会产生分段错误.这个项目是在 nachos 平台上为任何熟悉的人编写的，但是 List 的定义与 C++ 中的任何链表大致相同.对于不熟悉玉米片的人来说，'void thread' 是我的 'int main'.

During the execution of 'cI->client=which' a segmentation fault is produced. This project is being writting on the nachos platform for anyone that is familiar, however the definition of List is much the same as any linked list in C++. For anyone not familiar with nachos, 'void thread' is my 'int main'.

提前致谢.

推荐答案

你要创建clientInfo *cI，比如

clientInfo *cI = new clientInfo();

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