如何在构造函数中初始化 char 数组?

How can I initialize char arrays in a constructor?(如何在构造函数中初始化 char 数组?)

问题描述

我在声明和初始化 char 数组时遇到问题.它总是显示随机字符.我创建了一小段代码来展示我在更大的程序中尝试的内容:

I'm having trouble declaring and initializing a char array. It always displays random characters. I created a smaller bit of code to show what I'm trying in my larger program:

class test
{
    private:
        char name[40];
        int x;
    public:
        test();
        void display()
        {
            std::cout<<name<<std::endl;
            std::cin>>x;
        }
};
test::test()
{
    char name [] = "Standard";
}

int main()
{   test *test1 = new test;
    test1->display();
}

很抱歉，如果我的格式不好，我几乎无法弄清楚这个网站，更不用说如何修复我的代码了 :(

And sorry if my formatting is bad, I can barely figure out this website let alone how to fix my code :(

推荐答案

如果没有特殊原因不使用std::string，请使用std::string.

If there are no particular reasons to not use std::string, do use std::string.

但是如果你真的需要初始化那个字符数组成员，那么:

But if you really need to initialize that character array member, then:

#include <assert.h>
#include <iostream>
#include <string.h>
using namespace std;

class test
{
    private:
        char name[40];
        int x;
    public:
        test();
        void display() const
        {
            std::cout<<name<<std::endl;
        }
};

test::test()
{
    static char const nameData[] = "Standard";

    assert( strlen( nameData ) < sizeof( name ) );
    strcpy( name, nameData );
}

int main()
{
    test().display();
}

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