C++ 将 char 转换为 const char*

C++ convert char to const char*(C++ 将 char 转换为 const char*)

问题描述

基本上我只想循环遍历一串字符，将每个字符拉出，每个字符都必须是 const char* 类型，这样我就可以将它传递给函数.这是一个例子.感谢您的帮助.

Basically i just want to loop through a string of characters pull each one out and each one has to be of type const char* so i can pass it to a function. heres a example. Thanks for your help.

    string thestring = "abc123";
    const char* theval;
    string result;

    for(i = 0; i < thestring.length(); i++){
        theval = thestring[i]; //somehow convert this must be type const char*
        result = func(theval);
    }

推荐答案

string sym(1, thestring[i]);
theval = sym.c_str();

它为每个字符提供一个以 null 结尾的 const char*.

It gives a null-terminated const char* for every character.

这篇关于C++ 将 char 转换为 const char*的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！