“operator = must be a non-static member"是什么意思

What does quot;operator = must be a non-static memberquot; mean?(“operator = must be a non-static member是什么意思?意思?)

问题描述

我正在创建一个双链表，并重载了 operator= 以使列表中的另一个相等:

I'm in the process of creating a double-linked list, and have overloaded the operator= to make on list equal another:

template<class T>
void operator=(const list<T>& lst)
{
    clear();
    copy(lst);
    return;
}

但是当我尝试编译时出现此错误:

but I get this error when I try to compile:

container_def.h(74) : error C2801: 'operator =' must be a non-static member

另外，如果有帮助，第 74 行是定义的最后一行，带有}".

Also, if it helps, line 74 is the last line of the definition, with the "}".

推荐答案

正如它所说的:运算符重载必须是成员函数.(在类中声明)

Exactly what it says: operator overloads must be member functions. (declared inside the class)

template<class T>
void list<T>::operator=(const list<T>& rhs)
{
    ...
}

另外，从 = 返回 LHS 可能是个好主意，这样你就可以链接它(比如 a = b = c) - 所以让它list&list::operator=....

Also, it's probably a good idea to return the LHS from = so you can chain it (like a = b = c) - so make it list<T>& list<T>::operator=....

这篇关于“operator = must be a non-static member"是什么意思?意思?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！