remove_if equivalent for std::map(remove_if 等效于 std::map)
问题描述
我试图根据特定条件从地图中删除一系列元素.我如何使用 STL 算法做到这一点?
I was trying to erase a range of elements from map based on particular condition. How do I do it using STL algorithms?
最初我想使用 remove_if 但这是不可能的,因为 remove_if 不适用于关联容器.
Initially I thought of using remove_if but it is not possible as remove_if does not work for associative container.
是否有任何适用于地图的remove_if"等效算法?
Is there any "remove_if" equivalent algorithm which works for map ?
作为一个简单的选择,我想到了遍历地图并擦除.但是循环遍历地图并擦除安全选项吗?(因为擦除后迭代器无效)
As a simple option, I thought of looping through the map and erase. But is looping through the map and erasing a safe option?(as iterators get invalid after erase)
我使用了以下示例:
bool predicate(const std::pair<int,std::string>& x)
{
return x.first > 2;
}
int main(void)
{
std::map<int, std::string> aMap;
aMap[2] = "two";
aMap[3] = "three";
aMap[4] = "four";
aMap[5] = "five";
aMap[6] = "six";
// does not work, an error
// std::remove_if(aMap.begin(), aMap.end(), predicate);
std::map<int, std::string>::iterator iter = aMap.begin();
std::map<int, std::string>::iterator endIter = aMap.end();
for(; iter != endIter; ++iter)
{
if(Some Condition)
{
// is it safe ?
aMap.erase(iter++);
}
}
return 0;
}
推荐答案
差不多.
for(; iter != endIter; ) {
if (Some Condition) {
iter = aMap.erase(iter);
} else {
++iter;
}
}
如果您确实从中删除了一个元素,那么您最初拥有的会增加迭代器两次;您可能会跳过需要删除的元素.
What you had originally would increment the iterator twice if you did erase an element from it; you could potentially skip over elements that needed to be erased.
这是我在很多地方看到使用和记录的常用算法.
This is a common algorithm I've seen used and documented in many places.
您是正确的,迭代器在擦除后失效,但只有引用被擦除元素的迭代器,其他迭代器仍然有效.因此在 erase() 调用中使用 iter++.
You are correct that iterators are invalidated after an erase, but only iterators referencing the element that is erased, other iterators are still valid. Hence using iter++ in the erase() call.
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本文标题为:remove_if 等效于 std::map
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