c ++:可以矢量<Base>包含派生类型的对象?

c++: can vectorlt;Basegt; contain objects of type Derived?(c ++:可以矢量lt;Basegt;包含派生类型的对象?)

问题描述

标题几乎说明了一切.基本上，这样做是否合法:

The title pretty much says it all. Basically, is it legal to do this:

class Base {
    //stuff
}

class Derived: public Base {
    //more stuff
}

vector<Base> foo;
Derived bar;
foo.push_back(bar);

根据我看过的其他帖子，以下内容是可以的，但我不想在这种情况下使用指针，因为它更难使其线程安全.

Based on other posts I've seen, the following is okay, but I don't want to use pointers in this case because it's harder to make it thread safe.

vector<Base*> foo;
Derived* bar = new Derived;
foo.push_back(bar);

推荐答案

不，Derived 对象将是 sliced:所有额外的成员都将被丢弃.

No, the Derived objects will be sliced: all additional members will be discarded.

使用 std::vector 代替原始指针>.

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