C++ 按值而不是按位置擦除向量元素?

C++ Erase vector element by value rather than by position?(C++ 按值而不是按位置擦除向量元素?)

问题描述

vector<int> myVector;

让我们说向量中的值是这个(按这个顺序):

and lets say the values in the vector are this (in this order):

5 9 2 8 0 7

如果我想删除包含值8"的元素，我想我会这样做:

If I wanted to erase the element that contains the value of "8", I think I would do this:

myVector.erase(myVector.begin()+4);

因为这会擦除第 4 个元素.但是有没有办法根据值8"擦除元素?喜欢:

Because that would erase the 4th element. But is there any way to erase an element based off of the value "8"? Like:

myVector.eraseElementWhoseValueIs(8);

还是我只需要遍历所有向量元素并测试它们的值?

Or do I simply just need to iterate through all the vector elements and test their values?

推荐答案

std::remove() 代替:

#include <algorithm>
...
vec.erase(std::remove(vec.begin(), vec.end(), 8), vec.end());

这种组合也称为擦除-删除习语.

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