以毫秒为单位捕获时间

Capturing a time in milliseconds(以毫秒为单位捕获时间)

问题描述

以下代码用于打印日志中的时间:

The following piece of code is used to print the time in the logs:

#define PRINTTIME() struct tm  * tmptime;
time_t     tmpGetTime;
time(&tmpGetTime);
tmptime = localtime(&tmpGetTime);
cout << tmptime->tm_mday << "/" <<tmptime->tm_mon+1 << "/" << 1900+tmptime->tm_year << " " << tmptime->tm_hour << ":" << tmptime->tm_min << ":" << tmptime->tm_sec<<">>";

有什么办法可以增加毫秒数吗?

Is there any way to add milliseconds to this?

推荐答案

要获得毫秒级精度，您必须使用特定于您的操作系统的系统调用.

To have millisecond precision you have to use system calls specific to your OS.

在Linux中你可以使用

In Linux you can use

#include <sys/time.h>

timeval tv;
gettimeofday(&tv, 0);
// then convert struct tv to your needed ms precision

timeval 具有微秒精度.

在 Windows 中，您可以使用:

In Windows you can use:

#include <Windows.h>

SYSTEMTIME st;
GetSystemTime(&st);
// then convert st to your precision needs

当然，您可以使用 Boost 为您做到这一点:)

Of course you can use Boost to do that for you :)

这篇关于以毫秒为单位捕获时间的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！