C++ 二进制常量/字面量

C++ binary constant/literal(C++ 二进制常量/字面量)

问题描述

我正在使用一个众所周知的模板来允许二进制常量

I'm using a well known template to allow binary constants

template< unsigned long long N >
struct binary
{
  enum { value = (N % 10) + 2 * binary< N / 10 > :: value } ;
};

template<>
struct binary< 0 >
{
  enum { value = 0 } ;
};

所以你可以做类似二进制<101011011>::value 的事情.不幸的是，这对于 unsigned long long 有 20 位数字的限制.

So you can do something like binary<101011011>::value. Unfortunately this has a limit of 20 digits for a unsigned long long.

谁有更好的解决方案?

推荐答案

如果您的二进制值有前导零，这是否有效?前导零表示常量是八进制而不是十进制.

Does this work if you have a leading zero on your binary value? A leading zero makes the constant octal rather than decimal.

这会导致从该解决方案中挤出更多数字 - 始终以零开始您的二进制常量！然后将模板中的 10 替换为 8.

Which leads to a way to squeeze a couple more digits out of this solution - always start your binary constant with a zero! Then replace the 10's in your template with 8's.

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