C++ 异常会通过 C 代码安全地传播吗?

Will C++ exceptions safely propagate through C code?(C++ 异常会通过 C 代码安全地传播吗?)

问题描述

我有一个 C++ 应用程序，它调用 SQLite(SQLite 在 C 中)sqlite3_exec() 反过来又可以调用我在 C++ 中实现的回调函数.SQLite 被编译成静态库.

I have a C++ application that calls SQLite's (SQLite is in C) sqlite3_exec() which in turn can call my callback function implemented in C++. SQLite is compiled into a static library.

如果异常逃脱了我的回调，它会通过 SQLite 的 C 代码安全地传播到调用 sqlite3_exec() 的 C++ 代码吗?

If an exception escapes my callback will it propagate safely through the C code of SQLite to the C++ code calling sqlite3_exec()?

推荐答案

我猜这与编译器有关.但是，在回调中抛出异常将是一个非常糟糕的主意.要么它完全不起作用，要么 SQLite 库中的 C 代码将无法处理它.考虑这是否是 SQLite 中的一些代码:

My guess is that this is compiler dependent. However, throwing an exception in the callback would be a very bad idea. Either it will flat-out not work, or the C code in the SQLite library will be unable to handle it. Consider if this is some code in SQLite:

{
  char * p = malloc( 1000 );
  ...
  call_the_callback();  // might throw an exception
  ...
  free( p );
}

如果异常有效"，则 C 代码无法捕获它，并且 p 将永远不会被释放.当然，图书馆可能分配的任何其他资源也是如此.

If the exception "works", the C code has no possible way of catching it, and p will never be freed. The same goes for any other resources the library may have allocated, of course.

这篇关于C++ 异常会通过 C 代码安全地传播吗?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！